{"type":"video","version":"1.0","html":"<iframe src=\"https://www.loom.com/embed/5227145eb5254ca9b3835e47a627599e\" frameborder=\"0\" width=\"1838\" height=\"1378\" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>","height":1378,"width":1838,"provider_name":"Loom","provider_url":"https://www.loom.com","thumbnail_height":1378,"thumbnail_width":1838,"thumbnail_url":"https://cdn.loom.com/sessions/thumbnails/5227145eb5254ca9b3835e47a627599e-897fc1ae49a50dbe.gif","duration":620.591,"title":"1H Grade 3 Algebra","description":"In this video, I walk through a grade 3 algebra problem involving ages, where Chiara is 7 years older than Jay, and Martha is twice as old as Chiara, with their combined ages totaling 77. I set Jay's age as n, leading to the conclusion that Jay is 14, Chiara is 21, and Martha is 42, and I find the ratio of their ages. I also tackle a substitution problem using the equation v squared equals u squared plus 2af, calculating the final value of v. Additionally, I demonstrate how to isolate s in the equation. Please follow along and ensure you understand each step, as this will be crucial for your practice."}