{"type":"video","version":"1.0","html":"<iframe src=\"https://www.loom.com/embed/53afd0f3128a4840b529b58fd95fb764\" frameborder=\"0\" width=\"1840\" height=\"1380\" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>","height":1380,"width":1840,"provider_name":"Loom","provider_url":"https://www.loom.com","thumbnail_height":1380,"thumbnail_width":1840,"thumbnail_url":"https://cdn.loom.com/sessions/thumbnails/53afd0f3128a4840b529b58fd95fb764-3640c310f225e2e7.gif","duration":3589.643,"title":"9MA0 Stats - Set 3 - Binomial Distribution","description":"In this video, I discuss a question from Set Three on binomial distribution, specifically focusing on the mean total cloud cover from the large data set, which measures cloud cover in octas over 184 days from May to October 1987 in Leutges, Scotland. I explain how to calculate the probability of randomly selecting a day with a daily mean total cloud cover of six or greater by adding the frequencies of days with six, seven, and eight octas and dividing by the total number of days. I encourage you to follow along with the calculations and ensure you understand the process. This is a crucial concept as we prepare for upcoming assessments. Please review the data provided and practice similar problems."}