{"type":"video","version":"1.0","html":"<iframe src=\"https://www.loom.com/embed/97d3c12ef073437d9e71028e703cb193\" frameborder=\"0\" width=\"1920\" height=\"1440\" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>","height":1440,"width":1920,"provider_name":"Loom","provider_url":"https://www.loom.com","thumbnail_height":1440,"thumbnail_width":1920,"thumbnail_url":"https://cdn.loom.com/sessions/thumbnails/97d3c12ef073437d9e71028e703cb193-b116d3f257dc767e.gif","duration":177.745,"title":"Proving a Perfect Square Algebra Expression","description":"This Loom proves an algebraic identity by expanding and simplifying an expression involving x. It starts by expanding (3x + 1) squared using the formula (a + b) squared, then subtracting 2x times (4x - 3). After collecting like terms, it simplifies to x squared + 12x + 36. Finally, it factors the result as (x + 6) squared, showing the original expression equals a perfect square number for any value of x."}