{"type":"video","version":"1.0","html":"<iframe src=\"https://www.loom.com/embed/e9fe889f702548e8bc8b4c8493f576b0\" frameborder=\"0\" width=\"1838\" height=\"1378\" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>","height":1378,"width":1838,"provider_name":"Loom","provider_url":"https://www.loom.com","thumbnail_height":1378,"thumbnail_width":1838,"thumbnail_url":"https://cdn.loom.com/sessions/thumbnails/e9fe889f702548e8bc8b4c8493f576b0-b1614bd15208c875.gif","duration":2603.833,"title":"9FM0 CP2 - Set 7 - Volume of Revolution V2","description":"In this Loom I worked through four volume of revolution questions step by step, mainly using pi times the integral of x squared with respect to y. For the gold pendant with x equals cos theta plus a half sine 2 theta, I found the volume 1.6 pi cm cubed. For the paddling pool modeled by y equals ln 3.6x minus 2.6, I calculated k equals 2.6, volume up to depth H, and the water rising rate as 25.4 centimeters per hour when H equals 0.2 meters. I also found a berry volume of about 2.26 cm cubed and compared it to 200 cm cubed, then computed a chess piece volume about 6.11 cm cubed. No action was specifically requested from viewers."}