<?xml version="1.0" encoding="UTF-8"?><oembed><type>video</type><version>1.0</version><html>&lt;iframe src=&quot;https://www.loom.com/embed/1b1157340b7a4f76b60d59dce87901b8&quot; frameborder=&quot;0&quot; width=&quot;1280&quot; height=&quot;960&quot; webkitallowfullscreen mozallowfullscreen allowfullscreen&gt;&lt;/iframe&gt;</html><height>960</height><width>1280</width><provider_name>Loom</provider_name><provider_url>https://www.loom.com</provider_url><thumbnail_height>960</thumbnail_height><thumbnail_width>1280</thumbnail_width><thumbnail_url>https://cdn.loom.com/sessions/thumbnails/1b1157340b7a4f76b60d59dce87901b8-00001.jpg</thumbnail_url><duration>63</duration><title>S4 Q7</title><description>p: f(x) = -0.001160(x-251.5)^2 + 73.37
The vertical height, in meters, of the upper arch of the Harbor Bridge in Sydney, Australia, above the roadway of the bridge can be modeled by the function above, where x is the horizontal distance along the roadway, in meters, from the entry to the bridge. The graph of y=f(x) is shown in the xy-plane below. In the graph, the point (0, 0) represents the entry to the bridge. Which of the following points represents the exit from the bridge on the opposite end?</description></oembed>