video1.0<iframe src="https://www.loom.com/embed/288b3388a3a6437aaf6675533d7aefd4" frameborder="0" width="1838" height="1378" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>13781838Loomhttps://www.loom.com13781838https://cdn.loom.com/sessions/thumbnails/288b3388a3a6437aaf6675533d7aefd4-cd45df017c5e662f.gif4392.449In this video, I walk through a complex problem involving prims, nearest neighbour algorithms, and minimal spanning trees, specifically focusing on a scenario with six ponds and the time it takes to check them. I detail my calculations, revealing that the nearest neighbour from A is two less than the total length from D, leading to the conclusion that x equals 13. I emphasize the importance of understanding how to derive these values and the relationships between them. Additionally, I discuss how to apply this knowledge to find the quickest time to check all six ponds starting and finishing at A. I encourage viewers to follow along with the calculations and ensure they grasp the concepts presented.