<?xml version="1.0" encoding="UTF-8"?><oembed><type>video</type><version>1.0</version><html>&lt;iframe src=&quot;https://www.loom.com/embed/97d3c12ef073437d9e71028e703cb193&quot; frameborder=&quot;0&quot; width=&quot;1920&quot; height=&quot;1440&quot; webkitallowfullscreen mozallowfullscreen allowfullscreen&gt;&lt;/iframe&gt;</html><height>1440</height><width>1920</width><provider_name>Loom</provider_name><provider_url>https://www.loom.com</provider_url><thumbnail_height>1440</thumbnail_height><thumbnail_width>1920</thumbnail_width><thumbnail_url>https://cdn.loom.com/sessions/thumbnails/97d3c12ef073437d9e71028e703cb193-b116d3f257dc767e.gif</thumbnail_url><duration>177.745</duration><title>Proving a Perfect Square Algebra Expression</title><description>This Loom proves an algebraic identity by expanding and simplifying an expression involving x. It starts by expanding (3x + 1) squared using the formula (a + b) squared, then subtracting 2x times (4x - 3). After collecting like terms, it simplifies to x squared + 12x + 36. Finally, it factors the result as (x + 6) squared, showing the original expression equals a perfect square number for any value of x.</description></oembed>