video1.0<iframe src="https://www.loom.com/embed/c8dd5bc086df49eead2d43e2c7c2c55f" frameborder="0" width="1280" height="960" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>9601280Loomhttps://www.loom.com9601280https://cdn.loom.com/assets/img/og/slack-protected-video.gif66p: y = -16t^2 + 64t + 80 The equation above gives the height of an object above the ground, y, in feet, t seconds after it is launched from a platform. How many seconds after it is launched does the object reach the ground?