video1.0<iframe src="https://www.loom.com/embed/e9fe889f702548e8bc8b4c8493f576b0" frameborder="0" width="1838" height="1378" webkitallowfullscreen mozallowfullscreen allowfullscreen></iframe>13781838Loomhttps://www.loom.com13781838https://cdn.loom.com/sessions/thumbnails/e9fe889f702548e8bc8b4c8493f576b0-b1614bd15208c875.gif2603.833In this Loom I worked through four volume of revolution questions step by step, mainly using pi times the integral of x squared with respect to y. For the gold pendant with x equals cos theta plus a half sine 2 theta, I found the volume 1.6 pi cm cubed. For the paddling pool modeled by y equals ln 3.6x minus 2.6, I calculated k equals 2.6, volume up to depth H, and the water rising rate as 25.4 centimeters per hour when H equals 0.2 meters. I also found a berry volume of about 2.26 cm cubed and compared it to 200 cm cubed, then computed a chess piece volume about 6.11 cm cubed. No action was specifically requested from viewers.